2m^2+14m=16

Solution for 2m^2+14m=16 equation:

2m^2+14m=16

We move all terms to the left:

2m^2+14m-(16)=0

a = 2; b = 14; c = -16;
Δ = b2-4ac
Δ = 142-4·2·(-16)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-18}{2*2}=\frac{-32}{4}
=-8
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+18}{2*2}=\frac{4}{4}
=1
$